Summary for Banzhaf Voting System
By: Hannah Eisenberger
A couple weeks ago we learned
about Banzhaf Voting System. I am going to explain the steps that you have to
do to complete a problem. First you have to determine all the winning
coalitions. You have to determine if any of the votes can win the election by
itself. For example [6:4,3,2]. 4,3, or 2 cannot be equal to or have more than
6. However 4 and 3 do, 4 and 2 do, and all three of them together have enough
to be equal to 6 or more. Step two is to determine the critical players in each
winning coalition. To figure out if A (4), B (3), and C (2) is critical or not
count the number of votes the coalition has without each other (A, B, or C).
Back to the combinations from step one A and B both are critical because if one
of them leaves then they won’t win. Same with A and C. In A, B, and C only A is
critical because the coalition still wins if B leaves or if C leaves. The next step is to find the number of times
A, B, and C is critical total. So in this case its 5 times. Step four is to
find how many types EACH A, B, and C are critical. A is 3, B is 1, and C is 1.
Therefore the final step is to put these into fractions. So A is 3/5, B is 1/5,
and C is 1/5.
I have always been really confused on how to comprehend this voting system. I really do not how to go about completing it properly. After reading this summary however, I have gotten a better Idea on how go about figuring out exactly what to do. Very thought out and good information.
ReplyDeleteI thought this article was written very well Hannah. It was a lot easier to go back to this article for help then go through slide after slide of powerpoint.
ReplyDeleteI thought this article was written very well Hannah. It was a lot easier to go back to this article for help then go through slide after slide of powerpoint.
ReplyDelete